settype
(PHP 4, PHP 5)
settype — Присваивает переменной новый тип
Список параметров
-
var -
Преобразуемая переменная.
-
type -
Допустимыми значениями параметра
typeявляются:- "boolean" (или, начиная с PHP версии 4.2.0, "bool")
- "integer" (или, начиная с PHP версии 4.2.0, "int")
- "float" (возможно только c PHP 4.2.0, для предыдущих версий используйте устаревший вариант "double")
- "string"
- "array"
- "object"
- "null" (начиная с PHP версии 4.2.0)
Возвращаемые значения
Возвращает TRUE в случае успешного завершения или FALSE в случае возникновения ошибки.
Примеры
Пример #1 Пример использования settype()
<?php
$foo = "5bar"; // строка
$bar = true; // булевое значение
settype($foo, "integer"); // $foo теперь 5 (целое)
settype($bar, "string"); // $bar теперь "1" (строка)
?>
Примечания
Замечание:
Максимальное значение для "int" равно
PHP_INT_MAX.
- PHP Руководство
- Функции по категориям
- Индекс функций
- Справочник функций
- Расширения, относящиеся к переменным и типам
- Функции для работы с переменными
- boolval
- debug_zval_dump
- doubleval
- empty
- floatval
- get_defined_vars
- get_resource_type
- gettype
- import_request_variables
- intval
- is_array
- is_bool
- is_callable
- is_double
- is_float
- is_int
- is_integer
- is_long
- is_null
- is_numeric
- is_object
- is_real
- is_resource
- is_scalar
- is_string
- isset
- print_r
- serialize
- settype
- strval
- unserialize
- unset
- var_dump
- var_export
Коментарии
This settype() behaviour seems consistent to me. Quoting two sections from the manual:
"When casting from a scalar or a string variable to an array, the variable will become the first element of the array: "
<pre>
2 $var = 'ciao';
3 $arr = (array) $var;
4 echo $arr[0]; // outputs 'ciao'
</pre>
And if (like your code above) you do a settype on an empty variable, you'll end up with a one element array with an empty (not unset!) first element. So appeanding to it will start appending at index 1. As for why reset() doesn't do anything:
"When you assign a value to an array variable using empty brackets, the value will be added onto the end of the array."
It doesn't matter where the array counter is; values are added at the end, not at the counter.
Using settype is not the best way to convert a string into an integer, since it will strip the string wherever the first non-numeric character begins. The function intval($string) does the same thing.
If you're looking for a security check, or to strip non-numeric characters (such as cleaning up phone numbers or ZIP codes), try this instead:
<?
$number=ereg_replace("[^0-9]","",$number);
?>
/*** @return bool
* @param array[byreference] $values
* @desc Convert an array or any value to Escalar Object [not tested in large scale]
*/
function setobject(&$values) {
$values = (object) $values;
foreach ($values as $tkey => $val) {
if (is_array($val)) {
setobject($val);
$values->$tkey = $val;
}
}
return (bool) $values;
}
Instead of settype you could use:
<?php
$int=593; // $int is a integer
$int.=""; // $int is now a string
you must note that this function will not set the type permanently! the next time you set the value of that variable php will change its type as well.note that settype() will initialize an undefined variable. Therefore, if you want to preserve type and value, you should wrap the settype() call in a call to isset().
<?php
settype($foo, "integer");
echo("|$foo|");
?>
prints "|0|", NOT "||".
To get the latter, use:
<?php
if(isset($foo)) settype($foo, "integer");
echo("|$foo|");
?>
using (int) insted of the settype function works out much better for me. I have always used it. I personally don't see where settype would ever come in handy.To matt:
This function accepts a paremeter, which does not imply you using hardcoded stuff, instead you can let the user choose! \o/
As a part of a framework or something.
Plus, you can probably call this with call_user_func
Just a quick note, as this caught me out very briefly:
settype() returns bool, not the typecasted variable - so:
$blah = settype($blah, "int"); // is wrong, changes $blah to 0 or 1
settype($blah, "int"); // is correct
Hope this helps someone else who makes a mistake.. ;)
In trying to convert an array of strings to an array of ints,
I attempted to use settype with array_walk.
<?php
//$numArray is generated by another process
$numArray = array('13','14','33');
var_dump($numArray);
//my conversion function
function str_to_int($val){
//remember: settype($x, 'int') returns boolean (1=success, 0=failure)
//--> so return $x to return new value
settype($val,'int');
echo "<br />gettype = ".gettype($val)."<br />";
return $val;
}
array_walk($numArray,'str_to_int');
var_dump($numArray);
?>
The var_dumps both return the following:
<?php
array(3) { [0]=> string(2) "13" [1]=> string(2) "14" [2]=> string(2) "33" }
?>
The gettype echo will show the value as an integer.
So it seems that settype($val,'int') makes the conversion,
but the function return value remains a string.
Since settype returns a boolean, using
<?php $val = settype($val, 'int'); ?>
is not a option.
I resolved my array value conversion using this instead:
<?php
$numArray =
array_map(create_function('$value', 'return (int)$value;'),$numArray);
?>
Thanks to the posting here:
http://usrportage.de/archives/
808-Convert-an-array-of-strings-into-an-array-of-integers.html
Perhaps this will save someone else spinning wheels a bit.
Also thanks to robin at barafranca dot com for
pointing out the boolean return value of settype.
settype() has some really strange, potentially buggy behavior.
As noted by Michael Benedict, using settype() on a variable will initialize that variable. What is stranger is that using settype() on an uninitialized variable that you are treating as an array or object will also initialize the variable. So:
<?php
settype($foo->bar,"integer"); // stdClass Object ( [test] => 0 )
?>
This works for a chain of any length: $foo->bar['baz']->etc
Next we look at what happens if $foo is already set.
<?php
$foo = false;
settype($foo->bar,"integer"); // stdClass Object ( [test] => 0 )
?>
In and of itself, this wouldn't be problematic. It might even make sense. But in all other cases where $foo is defined, even if (boolean) $foo === false, it will throw an error unless $foo->bar is valid (i.e. $foo is an object already).
<?php
$foo = true;
settype($foo->bar,"integer"); // Notice: Trying to get property of non-object
?>
Note that you can't use this to convert a string 'true' or 'false' to a boolean variable true or false as a string 'false' is a boolean true. The empty string would be false instead...
<?php
$var = "true";
settype($var, 'bool');
var_dump($var); // true
$var = "false";
settype($var, 'bool');
var_dump($var); // true as well!
$var = "";
settype($var, 'bool');
var_dump($var); // false
?>
any digit except 0 or -0 are considered true in boolean, and any string except '0' or '' are also considered true.
<?php
$foo = '0';
settype($foo, 'boolean');
var_dump($foo); // false
$foo = 0;
settype($foo, 'boolean');
var_dump($foo); // false
$foo = "1";
settype($foo, "bool");
var_dump($foo); // Outputs: bool(true)
$bar = "0";
settype($bar, "bool");
var_dump($bar); // Outputs: bool(false)
If you attempt to convert the special $this variable from an instance method (only in classes) :
* PHP will silently return TRUE and leave $this unchanged if the type was 'bool', 'array', 'object' or 'NULL'
* PHP will generate an E_NOTICE if the type was 'int', 'float' or 'double', and $this will not be casted
* PHP will throw a catchable fatal error when the type is 'string' and the class does not define the __toString() method
Unless the new variable type passed as the second argument is invalid, settype() will return TRUE. In all cases the object will remain unchanged.
<?php
// This was tested with PHP 7.2
class Foo {
function test() {
printf("%-20s %-20s %s\n", 'Type', 'Succeed?', 'Converted');
// settype() should throw a fatal error, as $this cannot be re-assigned
printf("%-20s %-20s %s\n", 'bool', settype($this, 'bool'), print_r($this, TRUE));
printf("%-20s %-20s %s\n", 'int', settype($this, 'int'), print_r($this, TRUE));
printf("%-20s %-20s %s\n", 'float', settype($this, 'float'), print_r($this));
printf("%-20s %-20s %s\n", 'array', settype($this, 'array'), print_r($this, TRUE));
printf("%-20s %-20s %s\n", 'object', settype($this, 'object'), print_r($this, TRUE));
printf("%-20s %-20s %s\n", 'unknowntype', settype($this, 'unknowntype'), print_r($this, TRUE));
printf("%-20s %-20s %s\n", 'NULL', settype($this, 'NULL'), print_r($this, TRUE));
printf("%-20s %-20s %s\n", 'string', settype($this, 'string'), print_r($this, TRUE));
}
}
$a = new Foo();
$a->test();
?>
Here is the result :
Type Succeed? Converted
bool 1 Foo Object
(
)
Notice: Object of class Foo could not be converted to int in C:\php\examples\oop-settype-this.php on line 9
int 1 Foo Object
(
)
Notice: Object of class Foo could not be converted to float in C:\php\examples\oop-settype-this.php on line 10
float 1 Foo Object
(
)
array 1 Foo Object
(
)
object 1 Foo Object
(
)
Warning: settype(): Invalid type in C:\php\examples\oop-settype-this.php on line 14
unknowntype Foo Object
(
)
NULL 1 Foo Object
(
)
Catchable fatal error: Object of class Foo could not be converted to string in C:\php\examples\oop-settype-this.php on line 15
If the class Foo implements __toString() :
<?php
class Foo {
// ...
function __toString() {
return 'Foo object is awesome!';
}
// ...
}
?>
So the first code snippet will not generate an E_RECOVERABLE_ERROR, but instead print the same string as for the other types, and not look at the one returned by the __toString() method.
Hope this helps ! :)
Please note:
When using settype to convert indexed arrays to objects, the properties of the typed object will be integers:
A brief example:
$a = ['1', '2'];
settype($a, 'object');
var_dump($a);
// output
object(stdClass)#1 (2) {
["0"]=>
string(1) "1"
["1"]=>
string(1) "2"
}
<?php
/*
This example works 4x faster than settype() function in PHP-CGI 5.4.13 and
8x faster in PHP-CGI 7.1.3(x64) for windows
*/
$v = '12345';
$v = (int)$v;
$v = (string)$v;
?>