cal_days_in_month

(PHP 4 >= 4.1.0, PHP 5)

cal_days_in_monthВозвращает количество дней в месяце для заданного года и календаря

Описание

int cal_days_in_month ( int $calendar , int $month , int $year )

Эта функция возвратит количество дней в месяце month года year для заданного календаря calendar.

Список параметров

calendar

Календарь, используемый для вычисления

month

Месяц в выбранном календаре

year

Год в выбранном календаре

Возвращаемые значения

Количество дней в конкретном месяце выбранного календаря

Примеры

Пример #1 Пример использования cal_days_in_month()

<?php
$num 
cal_days_in_month(CAL_GREGORIAN82003); // 31
echo "Всего $num дней в Августе 2003 года";
?>

Коментарии

Here's a one-line function I just wrote to find the numbers of days in a month that doesn't depend on any other functions.

The reason I made this is because I just found out I forgot to compile PHP with support for calendars, and a class I'm writing for my website's open source section was broken. So rather than recompiling PHP (which I will get around to tomorrow I guess), I just wrote this function which should work just as well, and will always work without the requirement of PHP's calendar extension or any other PHP functions for that matter.

I learned the days of the month using the old knuckle & inbetween knuckle method, so that should explain the mod 7 part. :)

<?php
/*
 * days_in_month($month, $year)
 * Returns the number of days in a given month and year, taking into account leap years.
 *
 * $month: numeric month (integers 1-12)
 * $year: numeric year (any integer)
 *
 * Prec: $month is an integer between 1 and 12, inclusive, and $year is an integer.
 * Post: none
 */
// corrected by ben at sparkyb dot net
function days_in_month($month$year)
{
// calculate number of days in a month
return $month == ? ($year 28 : ($year 100 29 : ($year 400 28 29))) : (($month 1) % 30 31);
}
?>

Enjoy,
David Bindel
2004-01-01 23:06:24
http://php5.kiev.ua/manual/ru/function.cal-days-in-month.html
This will work great in future dates but will give the wrong answer for dates before 1550 (approx) when leap year was introduced and the calendar lost a year or two.
Sorry now to be more specific it has been a while sine I had to account for those later dates and had to take that into account but just a heads up for others to watch out.
2004-04-14 13:04:13
http://php5.kiev.ua/manual/ru/function.cal-days-in-month.html
<?php
# PHP Calendar (version 2.3), written by Keith Devens

function generate_calendar($year$month$days = array(), $day_name_length 3$month_href NULL$first_day 0$pn = array()){
   
$first_of_month gmmktime(0,0,0,$month,1,$year);

   
#remember that mktime will automatically correct if invalid dates are entered
    # for instance, mktime(0,0,0,12,32,1997) will be the date for Jan 1, 1998
    # this provides a built in "rounding" feature to generate_calendar()

   
$day_names = array(); #generate all the day names according to the current locale
   
for($n=0,$t=(3+$first_day)*86400$n<7$n++,$t+=86400#January 4, 1970 was a Sunday
       
$day_names[$n] = ucfirst(gmstrftime('%A',$t)); #%A means full textual day name

   
list($month$year$month_name$weekday) = explode(',',gmstrftime('%m,%Y,%B,%w',$first_of_month));
   
$weekday = ($weekday $first_day) % 7#adjust for $first_day
   
$title   htmlentities(ucfirst($month_name)).'&nbsp;'.$year#note that some locales don't capitalize month and day names

    #Begin calendar. Uses a real <caption>. See http://diveintomark.org/archives/2002/07/03
   
@list($p$pl) = each($pn); @list($n$nl) = each($pn); #previous and next links, if applicable
   
if($p$p '<span class="calendar-prev">'.($pl '<a href="'.htmlspecialchars($pl).'">'.$p.'</a>' $p).'</span>&nbsp;';
    if(
$n$n '&nbsp;<span class="calendar-next">'.($nl '<a href="'.htmlspecialchars($nl).'">'.$n.'</a>' $n).'</span>';
   
$calendar '<table class="calendar">'."\n".
       
'<caption class="calendar-month">'.$p.($month_href '<a href="'.htmlspecialchars($month_href).'">'.$title.'</a>' $title).$n."</caption>\n<tr>";

    if(
$day_name_length){ #if the day names should be shown ($day_name_length > 0)
        #if day_name_length is >3, the full name of the day will be printed
       
foreach($day_names as $d)
           
$calendar .= '<th abbr="'.htmlentities($d).'">'.htmlentities($day_name_length substr($d,0,$day_name_length) : $d).'</th>';
       
$calendar .= "</tr>\n<tr>";
    }

    if(
$weekday 0$calendar .= '<td colspan="'.$weekday.'">&nbsp;</td>'#initial 'empty' days
   
for($day=1,$days_in_month=gmdate('t',$first_of_month); $day<=$days_in_month$day++,$weekday++){
        if(
$weekday == 7){
           
$weekday   0#start a new week
           
$calendar .= "</tr>\n<tr>";
        }
        if(isset(
$days[$day]) and is_array($days[$day])){
            @list(
$link$classes$content) = $days[$day];
            if(
is_null($content))  $content  $day;
           
$calendar .= '<td'.($classes ' class="'.htmlspecialchars($classes).'">' '>').
                (
$link '<a href="'.htmlspecialchars($link).'">'.$content.'</a>' $content).'</td>';
        }
        else 
$calendar .= "<td>$day</td>";
    }
    if(
$weekday != 7$calendar .= '<td colspan="'.(7-$weekday).'">&nbsp;</td>'#remaining "empty" days

   
return $calendar."</tr>\n</table>\n";
}
echo 
generate_calendar(20101216,3,NULL,0,15$first_of_month$day_names$day_names[$n]);
#echo generate_calendar($year, $month, $days,$day_name_length,$month_href,$first_day,$pn);
?>
2007-07-19 02:28:28
http://php5.kiev.ua/manual/ru/function.cal-days-in-month.html
Remember if you just want the days in the current month, use the date function:
$days = date("t");
2007-12-04 18:55:47
http://php5.kiev.ua/manual/ru/function.cal-days-in-month.html

    Поддержать сайт на родительском проекте КГБ