filter_has_var
(PHP 5 >= 5.2.0)
filter_has_var — Проверяет существование переменной указанного типа
Описание
bool filter_has_var
( int
$type
, string $variable_name
)Список параметров
-
type -
Один из
INPUT_GET,INPUT_POST,INPUT_COOKIE,INPUT_SERVER,INPUT_ENV. -
variable_name -
Имя проверяемой переменной.
Возвращаемые значения
Возвращает TRUE в случае успешного завершения или FALSE в случае возникновения ошибки.
Коментарии
Please note that the function does not check the live array, it actually checks the content received by php:
<?php
$_GET['test'] = 1;
echo filter_has_var(INPUT_GET, 'test') ? 'Yes' : 'No';
?>
would say "No", unless the parameter was actually in the querystring.
Also, if the input var is empty, it will say Yes.
Through this example i think you can better understand
if ( !filter_has_var(INPUT_GET, 'email') ) {
echo "Email Not Found";
}else{
echo "Email Found";
}
Output
localhost/nanhe/test.php?email=1 //Email Found
localhost/nanhe/test.php?email //Email Found
http://localhost/nanhe/test.php //Email Not Found
Consider on second example
http://localhost/nanhe/test.php
$_GET['email']="info@nanhe.in";
if ( !filter_has_var(INPUT_GET, 'email') ) {
echo "Email Not Found";
}else{
echo "Email Found";
}
But output will be Email Not Found