date_parse_from_format

(PHP 5 >= 5.3.0)

date_parse_from_formatGet info about given date formatted according to the specified format

Description

array date_parse_from_format ( string $format , string $date )

Returns associative array with detailed info about given date.

Parameters

format

Format accepted by DateTime::createFromFormat().

date

String representing the date.

Return Values

Returns associative array with detailed info about given date.

Examples

Example #1 date_parse_from_format() example

<?php
$date 
"6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP"$date));
?>

The above example will output:

Array
(
    [year] => 2009
    [month] => 1
    [day] => 6
    [hour] => 13
    [minute] => 0
    [second] => 0
    [fraction] => 
    [warning_count] => 0
    [warnings] => Array
        (
        )

    [error_count] => 0
    [errors] => Array
        (
        )

    [is_localtime] => 1
    [zone_type] => 1
    [zone] => -60
    [is_dst] => 
)

See Also

Коментарии

It seems that the safest way to check for errors is not by checking the number of errors, but warnings instead. See the following example where "m" and "d" are swapped and thus not correct.

<?php
var_dump
date_parse_from_format('m.d.Y''18.10.2024') );

OUTPUT:
array(
12) {
  [
"year"]=>
 
int(2024)
  [
"month"]=>
 
int(18)
  [
"day"]=>
 
int(10)
  [
"hour"]=>
 
bool(false)
  [
"minute"]=>
 
bool(false)
  [
"second"]=>
 
bool(false)
  [
"fraction"]=>
 
bool(false)
  [
"warning_count"]=>
 
int(1)
  [
"warnings"]=>
  array(
1) {
    [
10]=>
   
string(27"The parsed date was invalid"
 
}
  [
"error_count"]=>
 
int(0)
  [
"errors"]=>
  array(
0) {
  }
  [
"is_localtime"]=>
 
bool(false)
}
?>

The function simply assigns 18 to the "month" field without errors!! So simply use an if-condition and check "warning_count" to detect possible errors.
2024-10-18 20:17:00
http://php5.kiev.ua/manual/ru/function.date-parse-from-format.html

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