mysqli::$insert_id

mysqli_insert_id

(PHP 5)

mysqli::$insert_id -- mysqli_insert_idReturns the auto generated id used in the last query

Description

Object oriented style

Procedural style

mixed mysqli_insert_id ( mysqli $link )

The mysqli_insert_id() function returns the ID generated by a query on a table with a column having the AUTO_INCREMENT attribute. If the last query wasn't an INSERT or UPDATE statement or if the modified table does not have a column with the AUTO_INCREMENT attribute, this function will return zero.

Note:

Performing an INSERT or UPDATE statement using the LAST_INSERT_ID() function will also modify the value returned by the mysqli_insert_id() function.

Parameters

link

Procedural style only: A link identifier returned by mysqli_connect() or mysqli_init()

Return Values

The value of the AUTO_INCREMENT field that was updated by the previous query. Returns zero if there was no previous query on the connection or if the query did not update an AUTO_INCREMENT value.

Note:

If the number is greater than maximal int value, mysqli_insert_id() will return a string.

Examples

Example #1 $mysqli->insert_id example

Object oriented style

<?php
$mysqli 
= new mysqli("localhost""my_user""my_password""world");

/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

$mysqli->query("CREATE TABLE myCity LIKE City");

$query "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
$mysqli->query($query);

printf ("New Record has id %d.\n"$mysqli->insert_id);

/* drop table */
$mysqli->query("DROP TABLE myCity");

/* close connection */
$mysqli->close();
?>

Procedural style

<?php
$link 
mysqli_connect("localhost""my_user""my_password""world");

/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

mysqli_query($link"CREATE TABLE myCity LIKE City");

$query "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
mysqli_query($link$query);

printf ("New Record has id %d.\n"mysqli_insert_id($link));

/* drop table */
mysqli_query($link"DROP TABLE myCity");

/* close connection */
mysqli_close($link);
?>

The above examples will output:

New Record has id 1.

Коментарии

I was having problems with getting the inserted id, and did a bit of testing. It ended up that if you commit a transaction before getting the last inserted id, it returns 0 every time, but if you get the last inserted id before committing the transaction, you get the correct value.
2004-11-03 13:44:00
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
I have received many statements that the insert_id property has a bug because it "works sometimes".  Keep in mind that when using the OOP approach, the actual instantiation of the mysqli class will hold the insert_id. 

The following code will return nothing.
<?php
$mysqli 
= new mysqli('host','user','pass','db');
if (
$result $mysqli->query("INSERT INTO t (field) VALUES ('value');")) {
   echo 
'The ID is: '.$result->insert_id;
}
?>

This is because the insert_id property doesn't belong to the result, but rather the actual mysqli class.  This would work:

<?php
$mysqli 
= new mysqli('host','user','pass','db');
if (
$result $mysqli->query("INSERT INTO t (field) VALUES ('value');")) {
   echo 
'The ID is: '.$mysqli->insert_id;
}
?>
2006-04-20 21:40:16
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
Автор:
When running extended inserts on a table with an AUTO_INCREMENT field, the value of mysqli_insert_id() will equal the value of the *first* row inserted, not the last, as you might expect.

<?
//mytable has an auto_increment field
$db->query("INSERT INTO mytable (field1,field2,field3) VALUES ('val1','val2','val3'),
('val1','val2','val3'),
('val1','val2','val3')"
);

echo 
$db->insert_id//will echo the id of the FIRST row inserted
?>
2007-05-04 04:10:09
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
Watch out for the oo-style use of $db->insert_id. When the insert_id exceeds 2^31 (2147483648) fetching the insert id renders a wrong, too large number. You better use the procedural mysqli_insert_id( $db ) instead.

[EDIT by danbrown AT php DOT net: This is another prime example of the limits of 32-bit signed integers.]
2008-07-22 11:58:08
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
The example is lack of insert_id in multi_query. Here is my example:
Assuming you have a new test_db in mysql like this:

create database if not exists test_db;
use test_db;
create table user_info (_id serial, name varchar(100) not null);
create table house_info (_id serial, address varchar(100) not null);

Then you run a php file like this:

<?php
define
('SERVER''127.0.01');
define('MYSQL_USER''your_user_name');
define('MYSQL_PASSWORD''your_password');

$db = new mysqli(SERVERMYSQL_USERMYSQL_PASSWORD"test_db"3306);
if (
$db->connect_errno)
  echo 
"create db failed, error is "$db->connect_error;
else {
 
$sql "insert into user_info "
   
"(name) values "
   
"('owen'), ('john'), ('lily')";
  if (!
$result $db->query($sql))
    echo 
"insert failed, error: "$db->error;
  else
    echo 
"last insert id in query is "$db->insert_id"\n";
 
$sql "insert into user_info"
   
"(name) values "
   
"('jim');";
 
$sql .= "insert into house_info "
   
"(address) values "
   
"('shenyang')";
  if (!
$db->multi_query($sql))
    echo 
"insert failed in multi_query, error: "$db->error;
  else {
    echo 
"last insert id in first multi_query is "$db->insert_id"\n";
    if (
$db->more_results() && $db->next_result())
      echo 
"last insert id in second multi_query is "$db->insert_id"\n";
    else
      echo 
"insert failed in multi_query, second query error is "$db->error;
  }
 
$db->close();
}
?>

You will get output like this:

last insert id in query is 1
last insert id in first multi_query is 4
last insert id in second multi_query is 1

Conclusion:
1 insert_id works in multi_query
2 insert_id is the first id mysql has used if you have insert multi values
2013-09-06 05:54:24
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
When using "INSERT ... ON DUPLICATE KEY UPDATE `id` = LAST_INSERT_ID(`id`)", the AUTO_INCREMENT will increase in an InnoDB table, but not in a MyISAM table.
2019-05-26 06:54:13
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
There has been no examples with prepared statements yet.

```php
$u_name = "John Doe";
$u_email = "johndoe@example.com";

$stmt = $connection->prepare(
    "INSERT INTO users (name, email) VALUES (?, ?)"
);
$stmt->bind_param('ss', $u_name, $u_email);
$stmt->execute();

echo $stmt->insert_id;
```

For UPDATE you simply change query string and binding parameters accordingly, the rest stays the same.

Of course the table needs to have AUTOINCREMENT PRIMARY KEY.
2021-02-02 17:39:19
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
If you try to INSERT a row using ON DUPLICATE KEY UPDATE, be aware that insert_id will not update if the ON DUPLICATE KEY UPDATE clause was triggered.

When you think about it, it's actually very logical since ON DUPLICATE KEY UPDATE is an UPDATE statement, and not an INSERT.

In a worst case scenario, if you're iterating over something and doing INSERTs while relying on insert_id in later code, you could be pointing at the wrong row on iterations where ON DUPLICATE KEY UPDATE is triggered!
2023-01-18 12:05:01
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html
What is unclear is how concurrency control affects this function.   When you make two successive calls to mysql where the result of the second depends on the first,  another user may have done an insert in the meantime.

The documentation is silent on this, so I always determine the value of an auto increment before and after an insert to guard against this.
2023-03-22 20:50:55
http://php5.kiev.ua/manual/ru/mysqli.insert-id.html

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